May wanted to solve 6x2 - 6x = x + 9. She decided to use the quadratic formula. Her values for a, b and c (in order) should be
A) 6, -5, 9
B) 6, -7, -9
C) 6, -5, -9
D) 6, 7, -9
2007-10-16 06:57:16 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
You have to balance the equation to get all your vaiables and coefficients on one side of the = and 0 on the other side.
First subtract 9 from both sides and you get 6x^2 -6x-9 = x
Then subtract x from both sides to get 6x^2-7x-9=0
The quadratic formula uses the coefficients from the equation ax^2+bx+c=0, so your a, b & c are 6, -7 and -9 or answer (B)
2007-10-16 07:04:40 · answer #1 · answered by Spaghetti Cat 5 · 0⤊ 0⤋
the eq is ax^2 + bx + c = 0
rearrange your equation you have
6x^2 - 7x - 9 = 0
so match the coeffs.
a = 6, b = -7 and c = -9 (b)
2007-10-16 07:02:10 · answer #2 · answered by norman 7 · 0⤊ 0⤋
Need to put in the form ax^2+bx+c = 0 so group like terms and set equal to zero...
2007-10-16 07:01:49 · answer #3 · answered by UA_Engineer_UAB_Med_Student 2 · 0⤊ 0⤋
6x2 - 6x = x + 9
6x² - 6x = x + 9
6x² - 7x -9 = 0
B) 6, -7, -9
2007-10-16 07:00:03 · answer #4 · answered by MamaMia © 7 · 1⤊ 0⤋
6x^2 - 6x = x + 9, so
6x^2 - 7x -9 =0.
so, (B)
2007-10-16 07:01:08 · answer #5 · answered by Twiggy 7 · 0⤊ 0⤋