[04]
(a^2 b^4)^3
=a^(2*3) b^(4*3)
=a^6 b^12
2007-10-16 05:44:20
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answer #1
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answered by alpha 7
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A^6 B^12
2007-10-16 05:41:27
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answer #2
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answered by Anonymous
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So it's:
(a^2 X b^4) + (a^2 X b^4) + (a^2 X b^4)
= A^6 + B^12
And that's the final answer, bc you can't simplify anymore.
2007-10-16 05:43:23
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answer #3
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answered by Anonymous
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just multiply the exponent by 3 (power)
so a^2(3) = a ^6
b^4 (3) = b^12
(a^6 b^12)
that is the right answer you can't add the power and the exponent in this problem
2007-10-16 05:53:35
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answer #4
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answered by nosa 2
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a^6 b^12
2007-10-16 05:44:06
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answer #5
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answered by lost gal 3
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The beauty of exponents is that they add.
So the answer is (a^2 b^4)^3 = a^5 b^7
2007-10-16 05:41:26
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answer #6
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answered by ignoramus 7
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you need to be somewhat clearer consisting of your powers in this element, it may get very confusing yet when 10a2b is 10a^(2)b then: 10a^(2)b(a^2-3a-4) 10a^(4)b-30a^(3)b-40a^(2)b Now divide by technique of a^(2)b 10a^2-30a-4 a^2-3a-4 (a-4)(a+a million) If this is the same as 0 then a is 4 and/or -a million
2016-10-21 06:29:13
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answer #7
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answered by desmangles 4
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exponent rules multiply exponent over exponent not add them so its
a^6 b^12
if you were to multiply the numbers a and b (same base) then their exponents would be added here you have to multiply them
someone tell that guy to do HIS homework how the heck did he come up with 1 anywayss
2007-10-16 06:04:51
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answer #8
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answered by sawwwaa 2
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You're getting some mixed answers, so here's the rules to remember.
(x-variable; m, n-constants)
(x^m)*(x^n) = x^(m+n)
(x^m)^n = x^(m*n)
2007-10-16 05:49:24
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answer #9
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answered by swrogueman 2
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1? listen in class and do your own homework!
2007-10-16 05:41:12
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answer #10
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answered by gell1981 3
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