English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-10-16 05:39:19 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

[04]
(a^2 b^4)^3
=a^(2*3) b^(4*3)
=a^6 b^12

2007-10-16 05:44:20 · answer #1 · answered by alpha 7 · 0 0

A^6 B^12

2007-10-16 05:41:27 · answer #2 · answered by Anonymous · 1 0

So it's:

(a^2 X b^4) + (a^2 X b^4) + (a^2 X b^4)

= A^6 + B^12

And that's the final answer, bc you can't simplify anymore.

2007-10-16 05:43:23 · answer #3 · answered by Anonymous · 0 0

just multiply the exponent by 3 (power)

so a^2(3) = a ^6

b^4 (3) = b^12

(a^6 b^12)
that is the right answer you can't add the power and the exponent in this problem

2007-10-16 05:53:35 · answer #4 · answered by nosa 2 · 0 0

a^6 b^12

2007-10-16 05:44:06 · answer #5 · answered by lost gal 3 · 0 0

The beauty of exponents is that they add.
So the answer is (a^2 b^4)^3 = a^5 b^7

2007-10-16 05:41:26 · answer #6 · answered by ignoramus 7 · 0 1

you need to be somewhat clearer consisting of your powers in this element, it may get very confusing yet when 10a2b is 10a^(2)b then: 10a^(2)b(a^2-3a-4) 10a^(4)b-30a^(3)b-40a^(2)b Now divide by technique of a^(2)b 10a^2-30a-4 a^2-3a-4 (a-4)(a+a million) If this is the same as 0 then a is 4 and/or -a million

2016-10-21 06:29:13 · answer #7 · answered by desmangles 4 · 0 0

exponent rules multiply exponent over exponent not add them so its
a^6 b^12
if you were to multiply the numbers a and b (same base) then their exponents would be added here you have to multiply them
someone tell that guy to do HIS homework how the heck did he come up with 1 anywayss

2007-10-16 06:04:51 · answer #8 · answered by sawwwaa 2 · 0 0

You're getting some mixed answers, so here's the rules to remember.

(x-variable; m, n-constants)

(x^m)*(x^n) = x^(m+n)
(x^m)^n = x^(m*n)

2007-10-16 05:49:24 · answer #9 · answered by swrogueman 2 · 0 0

1? listen in class and do your own homework!

2007-10-16 05:41:12 · answer #10 · answered by gell1981 3 · 0 1

fedest.com, questions and answers