x^2 - 2x > 0?

Answer 1

(x)(x - 2) > 0
Means
a)
x and (x - 2) both > 0
OR
b)
x and (x - 2) both < 0

from a):-
x > 0 , x > 2
x > 2

from b):-
x < 0 , x < 2
x < 0

Answer
x < 0 , x > 2

Answer 2

Taking X common
x(x-2)
x=0 and x= -2

Answer 3

x(x-2) > 0
x < 0 or x > 2
---------
Ideas: You can test x = -1 and x = 3
(-1)(-1-2) = 3 > 0
3(3-2) = 3 > 0

Answer 4

We can Re write the above as:
x^2-2^x>0
solving this we get
x is common so we can re write the above equation as: x(x-2)>0
This means that x!= 0 and (x-2)!=0
and both of them is of same sign
as if x is positive then (x-2) is also positive.
or if x is negative then (x-2) is also negative.
If we consider x as positive then x>2 always
If we consider x as negative then it takes any negative value.
So the range of x is:
any negative value or value greater than 2

Answer 5

x(x-2)>0
x>0 x>2

Answer 6

x^2 - 2x > 0
x (x-2) > 0
x > 0, (x-2) > 0

x > 0 or x > 2

x > 2

Answer 7

x^2-2x>0
x(x-2)>0

x>0 or x>2

Answer 8

I think it would be x>0 and x<-2
it want's the answer to be greater than 0, the previous solver just solved for x.

Answer 9

the answer is an in-equality, as is the question

answer = x>-2 because this also satisfies x>0 which is the second solution