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2- If there is only a peak in the voltage (without any
reputation in time) , is it possible to filter it by
one RC circuit ? if yes how ? how could we define the
frequency in this case ?

2007-10-16 05:36:02 · 4 answers · asked by Anonymous in Science & Mathematics Physics

4 answers

All potential drops on capacitor and current through circuit without load is 0.
There is no frequency but there is charachteristic time (period) during which voltage drop on resistor reduces e = 2.78 times.

2007-10-16 07:36:16 · answer #1 · answered by Alexey V 5 · 1 0

You will have to regulate the input voltage to some specific level and then choose one of the fixed voltage DC to DC step up converter circuits from that voltage. Two fairly simple circuits to track down.

2016-05-22 23:01:59 · answer #2 · answered by felipa 3 · 0 0

1. @ t=0, the voltage drop across the resistor is V, the drop across the capacitor is 0. As t-->infinity, the voltage drop across the capacitor goes to V, the voltage across the resistor goes to 0 (current stops flowing as the capacitor charges). For times < RC, the voltage of the capacitor goes as Vc = V(1 - e^(t/RC)), the voltage across the resistor is what is left, or, Vr = V - Vc. The frequency of a DC signal is 0.

2007-10-16 10:49:26 · answer #3 · answered by supastremph 6 · 0 0

In DC the condenser acts as an open circuit, that is, as if one of the two connections to the DC source is broken, So the conclusion is..? You think now! :-)

2007-10-16 06:03:14 · answer #4 · answered by physicist 4 · 0 2

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