magnetic torque?

Question

A 300 turn coil area of 25 cm^2 is placed in an 80 mT magnetic field. If the coil carries a current of 3.3 A, what is the magnitude of the maximum magnetic torque it could experience?

a) 20 N*m
b) 6.0 N*m
c) 0.13 N*m
d) 0.20 N*m
e) 0.060 N*m

please help

Answer 1

The maximum torque occurs when the loop is parallel to B and sin(theta)=1 (where theta is the angle between B and the normal to the loop).
Note that 25 cm^2 is not a square 25 cm on a side, it's 0.0025 m^2.
NIAB*1 = 300*3.3*0.0025*0.08 = 0.198 Nm, closest to answer D.

Answer 2

As far as I know

For a coil of N turns , net torque is t = N I A B sin(q)
so where's sin(q)
where as
N=300
A=25/100=0.25mraise to the power 2
B=80mT
I=3.3A