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A velocity selector for ions uses perpendicular electric and magnetic fields. If the electric field used were 800 V/m, what magnetic field would allow the selection of a velocity of 4000 m/s??

a) 0.040 T
b) 0.080 T
c) 0.16 T
d) 0.20 T
e) 0.50 T

2007-10-16 05:06:57 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

E = 800V/m, v = 4000m/s

electric force = magnetic force
qE = qvB
so
B = E/v = 800/4000 = 0.2T

,.,.,.,.,.,.,.,.,

2007-10-16 06:19:59 · answer #1 · answered by The Wolf 6 · 2 0

Eq=Bqv
B=E/v
B=800/4000
B=0.2 T

2007-10-16 07:06:18 · answer #2 · answered by Anonymous · 1 0

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