how do you solve this math equation?

Question

1/x +3/x^2
------------------------
1 + 1/x -6/x^2

Answer 1

Answer it already people, don't placehold!

1/x +3/x^2
------------------------
1 + 1/x -6/x^2


Multiply numerator and denominator by x² to get:

x + 3
-----------
x² + x - 6

Write denominator x² + x - 6 as (x-2)(x+3), then cancel terms of (x+3) from numerator and denominator

Your simplified term becomes:

1/(x-2)

Answer 2

A major difficulty on this program is the inability to show fractions:

Your problem re-written

[{1/x + 3/x²} all over {1 + 1/x - 6/x²}]

Solve first part

Common Denominator is x²

x into x² = x
x² into x² = 1
now multiply 1 by 3

First part is now
[{x + 3} / x²]

Solve Second part

again Common Denominator is x²
1 into x² = x²
x into x² = x
x² into x² multiply by 6

Second part is now
[{x² + x - 6} / x²]


Rewrte the whole thing

([{x + 3} / x²] / [{x² + x - 6} / x²])

Rearrange and 'Cross-Multiply'
{x + 3} / {x² + x - 6}

Now you can finish off ...

Answer 3

X each term by x^2

(x + 3)/(x^2 + x -6) = (x+3)/(x+3)(x-2)= 1/(x-2)

Answer 4

Multiply both numerator and denominator with x^2, and you can see that the numerator is x+3 while the denominator is x^2 + x - 6 or (x + 3)(x - 2) when factored. You can cancel afterwards and you get 1/(x - 2) as final answer.

Answer 5

1/x +3/x^2
------------------------
1 + 1/x -6/x^2
1/x +3/x^2 ÷ 1 + 1/x -6/x^2
= x + 3/x^2 ÷ x^2 + x – 6/x^2
= x + 3/x^2 ÷ x^2 +3 x – 2x – 6/x^2
= x + 3/x^2 ÷ x^2 +3 x – 2x – 6/x^2
= x + 3/x^2 ÷ x ( x +3) ( x – 2/x^2
= x + 3/x^2 ÷ ( x +3) ( x – 2/x^2
= (x + 3) / ( x +3) ( x – 2)
= 1 /(x – 2)

Answer 6

1/x +3/x^2
------------------
1 + 1/x -6/x^2

Multiply the big numerator and big denominator by x^2 to clear the little fractions

x + 3
- - - - - - - -
x^2 + x - 6

x + 3
- - - - - - - - - -
(x + 3)(x - 2)

1
- - - -
x - 2

Answer 7

Factor the top. Then factor the bottom.

Multilply the top an the bottom by X^2:

x^2* ( 1/x+3/x^2) x + 3
--------------------------- = -------------------------
x^2 * (1 + 1/x -6/x^2) x^2 + x - 6

Now you can factor the bottom:


x + 3 x + 3
--------------------------- = -------------------------
x^2 + x - 6 (x + 3)(x-2)

Answer 8

Multiply the entire equation by x^2 to get rid of all the small fractions

x+ 3
----------
x^2 + x - 6

Now factor the bottom

x+3
-------------
(x +3)(x-2)

The x+3 cance each other out

so you are left with

1
---------
(x-2)

Hope this helps

Answer 9

Multiply the whole thing by:

x^2
------
x^2

Then is will become clearer of what you need to do.

I will not tell you the whole answer. You should figure this out.

The final answer will look kind of like this: (Note this is not the answer but to be used to let you know that you are on the right track.)

1
------------
(x +/- ?)

Please note, my answer is incorrect, but if you follow my hint above, you should get to an answer that looks like what I put here.

Answer 10

What does it =?
The whole definition of an equation is one side equals the other