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d(squared) - 5d + 6 = 0

2007-10-16 02:56:59 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

[02]
It is a quadratic equation
d^2-5d+6=0
d^2-3d-2d+6=0
d(d-3)-2(d-3)=0
(d-3)(d-2)=0
The product of two or more numbers,terms or expressions cannot be zero until and unless one of them is zero
Therefore,either d-3=0 or d-2=0
If d-3=0,then d=3
If d-2=0,then d=2
Therefore d=3 or 2

2007-10-16 03:07:53 · answer #1 · answered by alpha 7 · 0 0

d^2 - 5d + 6 = 0

find factors of +6 that can add up to -5

+6&+1
or
-6&-1
or
+3&+2
or
-3&-2

in this case, -3&-2 are the only ones that could add up to -5

so (d - 3)(d - 2) = 0

d= 3, d= 2

2007-10-16 10:07:05 · answer #2 · answered by Anonymous · 0 0

d = 3
3(squared) - 5*3 + 6 = 0
9 - 15 + 6 = 0

2007-10-16 10:03:38 · answer #3 · answered by Bigfoot 3 · 0 0

A quadratic equation.
d^2 - 5d + 6 = 0
Factored:
(d - 3)(d - 2) = 0
Solutions:
d - 3 = 0
d = 3

d - 2 = 0
d = 2.

2007-10-16 10:02:53 · answer #4 · answered by S. B. 6 · 0 0

I believe I answered a question like this earlier - the same method works here.

What factor pairs of 6 (two numbers that multiply to 6) have a sum of -5?

The answer is -2 and -3!

So,

(d - 2) (d - 3) = 0

So the solutions to d are {2, 3}

Enjoy!

2007-10-16 10:03:00 · answer #5 · answered by zelljrc 2 · 0 0

x-kate-x

Use FOIL again and factorize

d^2 -5d +6 =0 ; factorize
(d-3)(d-2) =0

d= 3 or 2.

Note when using FOIL (d*d, then -2d, -3d, then +6)

See it now?

Hope this helps.

2007-10-16 10:04:07 · answer #6 · answered by pyz01 7 · 0 0

It's obvious that you knew what it was, so I don't understand why you're asking about it, unless, of course, you were just trying to get someone to do your homework for you.

2007-10-16 15:57:52 · answer #7 · answered by skaizun 6 · 0 0

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