x+1<2(x+3)?

Question

solve and graph

Answer 1

x + 1 < 2x + 6
- 5 < x
x = - 5 is a vertical line thro` (- 5 , 0)
The required graph is then a shaded region to the right of the dotted verical line x = - 5.
The dotted line is not part of required region.

Answer 2

First you need a starting point so make them equal.

x+1=2x+6 so x= -5 convert back and x > -5

always check the answer

-5+1<2(-5+3) or -4<2(-2) so -4<-4 this is where the graph starts with an open circle .

now plug in other numbers to double check

-3+1< 2(-3+3) so -2<0 works so the next point is -2.

So your graph will be on the x axis and go from -5 (open circle) to infinity.

Simple enough?

Answer 3

X+1<2(X+3)
X+1<2X+6
X-5<2X
-5

Answer 4

x+1<2(x+3)
==> x+1 < 2x+6
==> x < 2x+5
==> -2x + x < 5
==> -x < 5
==> x > -5

So in graph this is the area to the right of the line x = -5

Answer 5

x > -5.(vertical line passing through the pt. parallel to the y axis) The graph will be x = -5 (dotted line) and shade the area towards the origin.

Answer 6

lmao... this is kid's play! im more used to integration :P

x+1 < 2x + 6
-5 x> -5

thus x belongs to (-5, +infinity)
no graph dude, jus a number line, draw the number line and draw a line above -5 extending to +ve infinity.

Answer 7

Minus 7. (You had no answers, so I thought I'd just put anything. Don't put it in your exam-come up with your own random number. Don't forget to factorise, blah blah blah)

Answer 8

i also have my own hw so dont rely on me!

Answer 9

do ur own hm

Answer 10

i+(dont)-know:p