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2007-10-16 00:15:04 · 7 answers · asked by Ginga-Ninja 1 in Science & Mathematics Mathematics

7 answers

3x = 1 (mod 5) is determined when their units is 1 or 6.
By using trial and error, we got :
2,7,12,17,...
We must find the pattern.
Use the formula :
An = b(n-1)+a
a is the 1st term, so a = 2.
b is the difference, so b = 5
An = 5(n-1)+2 = 5n - 5 + 2 = 5n - 3
So, when n is a natural number, x=5n-3 is a solution to 3x=1(mod5)

2007-10-16 00:44:52 · answer #1 · answered by wangsacl 4 · 0 0

I don't know how to solve congruences the easy way,
so I have to go back to basics.

3x ≡ 1 (mod 5)

This means that (3x - 1) is exactly divisible by 5.
So we can let an integer, J = (3x - 1) / 5

Therefore, x = (5J + 1) / 3
Dividing as far as we can gives : x = J + (2J + 1) / 3

These are all integers, so let K = (2J + 1) / 3
Therefore, J = (3K - 1) / 2

Again, dividing as far as we can gives : J = K + (K - 1) / 2

All integers again, so let M = (K - 1) /2
Therefore, K = 2M + 1. Now we are rid of fractions.

Substituting back, with K = 2M + 1 gives :
J = 3M + 1

and back further gives : x = 5M + 2

Now let M take on the values 0, 1, 2, 3, 4, 5, ...

Thus, x = 2, 7, 12, 17, 22, 27, ...

So the solution is : x = 5M + 2
for M = 0, 1, 2, 3, ...

2007-10-16 02:13:38 · answer #2 · answered by falzoon 7 · 0 0

3x - 5 = 1
3x = 6
x = 2

thats the first value of x,
just add 5 the next values, thats is

2nd value = 2 + 5 = 7
check : 3*7 = 21 = 1 (mod 5)

3rd value = 7 + 5 = 12
check : 3 * 12 = 36 = 1 (mod 5)

4th value = 12 + 5 = 17
check: 3 * 17 = 51 = 1 (mod 5)

5th value: 17 + 5 = 22
check: 3 * 22 = 66 = 1 ( mod 5)


and so on..

2007-10-16 01:11:53 · answer #3 · answered by jen ol 3 · 0 0

Solving Modulus Equations

2016-11-13 00:33:37 · answer #4 · answered by ? 4 · 0 0

I think you mean 3 times x is congruent to 1 modulo 5. So, we have to find the positive integers x such that 5 divides 3x -1.This happens if, and only if, 3x -1 ends in 0 or 5, that is, if, and only if, 3x ends in 1 or in 6.

3x ends in 1 if, and only if, x ends in 7, that is, x s a number like 7, 17, 27...So, the numbers of the form x = 7 + 10(n-1)= 10n -3.

3x ends in 6 if, and only if, x ends in 2, that is, if and only if x is even.

So, the solution to your congruence is the set {x | x = 10n -3 or x = 2n, n positive integer}

2007-10-16 00:59:51 · answer #5 · answered by Steiner 7 · 0 0

Did you mean 3 times x or 3 to the power of?

2007-10-16 00:23:03 · answer #6 · answered by Ali 3 · 0 1

x=0 coz any number with the power of zero is one!

or if u mean 3x well, srry i dont know!

2007-10-16 00:27:57 · answer #7 · answered by Anonymous · 0 1

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