Find the zeros in the polynomial function
P(x)=2x^ 4+3x^3-4x^2-3x+2
2007-10-15 21:14:54 · 3 answers · asked by K Rose 3 in Science & Mathematics ➔ Mathematics
the possible roots are
+/- 1, +/- 2, +- (1/2)
by synthetic division, the roots are solved to be 1, 1/2, -2, and -1
2007-10-15 21:21:39 · answer #1 · answered by tootoot 3 · 0⤊ 0⤋
P(x) 2^4 + 3x^3 -4x^2 -3x + 2
By synthetic division
-1: 2 3 -4 -3 2
-2 -1 5 -2
With a remainder of 0 therefore
x-1 is a factor
-1 is a zero.
Its been a long time …. But I think its right.
when i submit this : its truncated.... the -2 is below the 3 ... etc.
2007-10-16 04:35:47 · answer #2 · answered by TicToc.... 7 · 0⤊ 0⤋
By synthetic division (and some trial and errors), the roots are 1, -1, -2, and 1/2.
2007-10-16 05:36:58 · answer #3 · answered by wolfwood 2 · 0⤊ 0⤋