A delivery truck travels 18 blocks north, 10 blocks east, and 16 blocks south. What is its final displacement?

Answer 1

The north and south cancel, leaving:

2 blocks north, 10 blocks east

Using th Pythagorean Theorem:

displacement= √[(2)^2+(10)^2]

= 2√26 blocks

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Answer 2

2

Answer 3

Distance north is 18blocks -16blocks = 2 blocks north. Distance east is 10blocks - 0blocks = 10 blocks east. The path looks like a right triangle that has sides representing distances 2 blocks north and 10 blocks east and the hypotenuse which is the displacement. By pythagoras thm. this is [2^2 + 18^2]^1/2 = 104^1/2 = approx. 10.2 blocks northeast.

Answer 4

north and south are opposites so you can detract them from each other. East's counterpart West isn't mentioned so that's "0 blocks west" if you want to use the same method

you're going further north than you are south, so you detract south from north (18-16) = 2 blocks North

for east and west (I'll explain it the same way so you can use it for other problems like these in the future): 10 east - 0 west = 10 east.

Final displacement of the delivery truck is two blocks north, ten blocks east from the starting point.

I hope you understood my explanation.

Answer 5

Two blocks North and 10 East is your displacement in terms of blocks. Should your displacement be expressed any way - in degrees or something?

Answer 6

Vertical
18 - 16 = 2
Horizontal
10
Coordinates are (10 , 2)
Magnitude = √(10² + 2²) = √104 = 2√26
Angle, θ = tan^(-1)(2 / 10)
θ = 11.3 °

Displacement 2√26 /_11.3°

Answer 7

Ten blocks east and one block north.

Answer 8

104^(1/2) to the north east

Answer 9

use the right triangle:

Resultant displacement:

sqr root of (18-16)^2 + (10)^2 or sqr root of 104.

Answer 10

A hole lotof blocks !!!