Elementary Algebra???

Question

2x+1= - (x+3)

a) -4/3
B) -2
c) 4
d) 2/3

and why

Answer 1

A...
2x+1=-x-3
2x+x=-3-1
3x=-4
x=-4/3

Answer 2

a) - 4/3 is the correct answer
2x+1= - (x+3) bring - sign into parenthesis
2x + 1 = - x - 3 Add x to both sides of the equation
2x + 1 + x = - x - 3 + x
3x + 1 = - 3 Subtract 1 from both sides of the equation
3x + 1 - 1 = - 3 -1
3x = -4
x = - 4/3 ANSWER a) is correct

check answer plug - 4/3 into the original equation
2x+1= - (x+3)
2(-4/3)+1= - ((-4/3)+3)
-8/3 + 1 = 4/3 - 3
-8/3 + 3/3 = 4/3 - 9/3
-5/3 = -5/3 checks out

Answer 3

2x+1= - (x+3)
2x+1= -x-3 (multiplying -1 to the bracket)
2x+x= -3-1 (x terms on LHS and constants on RHS)
3x= -4
x= -4/3

therefore ans is a) -4/3

Answer 4

2x+1 = -(x+3)
opening bracket
2x+1 = -x-3
transposing
2x+x = -3-1 = -4
adding terms containing x and constant terms
3x = -4
dividing both sides by 3
x = -4/3
'A' therefore is the correct answer.

Answer 5

2x + 1= -1x + -3
+1x+ 1 = +1x + -3 get your x's to one side by adding 1x to each side
3x + 1 = -3
3x + -1 = -1 + -3 get your numbers to the other side by subtracting -1 to both sides
3x = -4 divide each side by 3 to get your x by itself
x = -4/3
your answer is a

Answer 6

2x + 1 = -(x+3)
2x + 1 = -x - 3
3x = -4
x = -4/3

Answer 7

this question is almost too obscure to respond to particularly yet i'm guessing you will in all probability flow deeper into graphing, like discovering approximately parabolas, hyperbolas, circles and ellipses, consistent with probability discovering approximately e and logs, imaginary numbers and discovering approximately matrices. lots of this relies off of effortless algebra. I doubt that it's going to conceal techniques from Calculus yet Calculus will use the techniques you have found out in Algebra.

Answer 8

2x + 1 = -(x + 3)
2x + 1 = -x - 3
2x + 4 = -x
4 = -3x
4/-3 = -3x/-3
-4/3 = x

Answer 9

2x + 1 = -(x+3)
2x + 1 = -x -3
3x = -4
x = -4/3

so it is A

Answer 10

2x + 1 = - x - 3
3x = - 4
x = - 4/3
OPTION a)