Basically, I just want to know how to solve this. I was not given any other information, so I do not know how to approach this problem. I would greatly appreciate it if you showed the set-up as well as explanation of how you got to the answer. Thanks in advance!
2007-10-15 18:59:57 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
you are given 3M of H2SO4. calculate its ph. ph= -log[H+].
to find [H+], multiply 3 molar by two. (since there are two H in H2SO4) then you will get the concentration of H+
3M(2)= 6M H2
then substitute to the formula:
pH= -log [6]
then you have the pH. to get the pOH, use this formula,
pOH= 14-pH
then you have the pOH. then substitute the pOH to this formula.
pOH= -log [OH-]
[OH-] =e^x (pOH) wherein e^x is your antilog...
then you have the answer! ^_^
2007-10-15 19:17:00 · answer #1 · answered by blueice 2 · 1⤊ 0⤋
There's a much easier way:
[OH-] = Kw/[H+] = 10-14/6
2007-10-16 03:49:13 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋