Help with chemistry (calculate # of molecules present)?

Question

Calculate the # of molecules present

5.23 g of benzene, C6H6


Please show work and steps.
Thanks for your help.

Answer 1

First determine # of moles benzene:

5.23g/78g/mol = 0.0671mol

Now, multiply by avogodro's number:

0.0671mol x 6.02 x 10^23molecules/mol =

4.04 x 10^22molecules.

Answer 2

First calculate the mol of C6H6 present.

5.23g X 1 mol/78 g = 0.067 mol of C6H6

The definition of a mol is that 6.023 x 10^23 molecules be present so do the conversion:

0.067 mol X (6.023 x 10^23 molecules/1 mol) = 4.04 x 10^22 molecules of C6H6 present.

Answer 3

you are given 5.23g of benzene and c6h6. you must find the number of moles of benzene. do this by dividing 5.23 by the molercular weight of C6H6. (mole= mass/ molecular mass)then multiply the answer to the avogadro's number (6.022x 10^23) then that's it! the answer you got is the number of molecules of benzene. (1 mole =6.022x 10^23 units wherein it can be atoms, molecules or ions) ^_^

Answer 4

5.23g x 6.022 x 10^23 =

3.15x10^24