Solve
2007-10-15 18:23:45 · 11 answers · asked by emily s 1 in Science & Mathematics ➔ Mathematics
7y-2(y-8)=9y-(5y+13)
or 5y + 16 = 4y - 13
or y = - 29
2007-10-15 18:27:59 · answer #1 · answered by ib 4 · 0⤊ 0⤋
7y - 2(y-8) = 9y - (5y+13) Multiply to eliminate parethesis
7y - 2(y-8) = 9y - (5y+13)
7y - 2y -2(-8) = 9y -5y -13
5y + 16 = 4y - 13 Subtract 4y and 16 from both sides
5y + 16 - 4y -16 = 4y - 13 - 4y -16
y = -29 ANSWER
Check answer plug y = -29 into the original equation
7y - 2(y-8) = 9y - (5y+13)
7(-29) - 2(-29-8) = 9(-29) - (5(-29)+13)
-203 - 2(-37) = -261 - (-145 +13)
-203 + 74 = -261 + 132
-129 = -129 checks out
2007-10-16 01:48:49 · answer #2 · answered by r r 5 · 0⤊ 0⤋
7y - 2(y - 8) = 9y - (5y + 13)
7y - 2y + 16 = 9y - 5y - 13
y = - 29
Answer: y = - 29
Proof:
7(- 29) - 2(- 29 - 8) = 9(- 29) - (5[- 29] + 13)
- 203 - 2(- 37) = - 261 - (- 145 + 13)
- 203 + 74 = - 261 - (- 132)
- 129 = - 261 + 132
- 129 = - 129
2007-10-16 01:35:53 · answer #3 · answered by Jun Agruda 7 · 3⤊ 0⤋
7y - 2(y - 8) = 7y - 2y + 16 = 5y + 16
= 9y - (5y + 13) = 4y - 13.
5y + 16 = 4y - 13.
y = 3.
2007-10-16 01:28:13 · answer #4 · answered by Chase 3 · 1⤊ 1⤋
7y - 2y + 16 = 9y - 5y - 65
5y + 16 = 4y - 13
y = - 29
2007-10-16 02:55:58 · answer #5 · answered by Como 7 · 0⤊ 0⤋
7y-2(y-8)=9y-(5y+13)
7y-2y+16=9y-5y-13
collect like terms
7y-2y-9y+5y=-13-16
y=-29
2007-10-16 04:21:23 · answer #6 · answered by Gabriel 3 · 0⤊ 0⤋
7y-2(y-8)=9y-(5y+13)
7y-2y+16=9y-5y-13
5y+16=4y-13
y+16=-13
y= -29
2007-10-16 01:36:00 · answer #7 · answered by flyingbananabutterflies 2 · 0⤊ 0⤋
7y-2y+16=9y-5y-13
5y+16=4y-13
y=-29
you just need to distribute and add like terms
2007-10-16 01:34:25 · answer #8 · answered by sawwwaa 2 · 0⤊ 0⤋
7y-2y+16=9y-5y-13
5y+16=4y-13
5y-4y=-16-13
y= -29
2007-10-16 01:38:03 · answer #9 · answered by nuve 1 · 0⤊ 0⤋
I agree that it is - 29.
5y + 16 = 4y - 13
5y - 4y = -13 - 16
y = -29
2007-10-16 01:33:16 · answer #10 · answered by tf1sh13 1 · 0⤊ 0⤋