(NH4)2[AuCl4]
a) ammoniumtetrachlorogold(II)
b) ammonium tetrachloroaurate(II)
c) ammonium chloroaurate(II)
d) ammonium tetrachloroaurate(III)
e) amminetetrachloroaurate(II)
2007-10-15 18:10:46 · 4 answers · asked by Just me 1 in Science & Mathematics ➔ Chemistry
It's answer b.
2007-10-15 18:16:36 · answer #1 · answered by Flying Dragon 7 · 0⤊ 1⤋
The answer is B.
To break down the name ...
It is aurate, since the element is gold and the complex has a negative charge.
Ammonium is the counter ion.
Tetracholoro- Four chloro- ligands.
and (II) for the oxidation, since each chloro is -1, the NH4 is +1 and the compound is neutral. -4 from the chloro, +2 from NH4 leaves +2 from gold.
2007-10-15 18:21:30 · answer #2 · answered by starfall_48 1 · 1⤊ 0⤋
c. ammonium chloraurate (II)
2007-10-15 18:15:53 · answer #3 · answered by mickey m 1 · 1⤊ 1⤋
b is the answer.
2007-10-15 18:20:55 · answer #4 · answered by Dr. Eddie 6 · 0⤊ 0⤋