2x(squared)+8x+6
3x(squared)-12x+9
4x(squared)-x-14
2007-10-15 16:48:41 · 5 answers · asked by Arête 3 in Science & Mathematics ➔ Mathematics
2(x^2+4x+3)=2(x+3)(x+1)
so what you would do is take out the highest number and then factor.
example above
2007-10-15 16:54:33 · answer #1 · answered by Wito Works Well (alliteration) 2 · 1⤊ 0⤋
2x^2 + 8x + 6
= 2(x^2 + 4x + 3)
= 2(x + 3)(x + 1)
3x^2 - 12x + 9
= 3(x^2 - 4x + 3)
= 3(x - 3)(x - 1)
4x^2 - x - 14
= (4x + 7)(x - 2)
2007-10-15 16:55:56 · answer #2 · answered by Quocamus 2 · 1⤊ 0⤋
a) (2x + 2) (x +3) = 0 ; x = -1 ; x = -3
b) (3x - 3) (x - 3) = 0 ; x = 1 ; x = 3
c) (4x + 7) (x - 2) = 0 ; x = -7/4 ; x = 2
2007-10-15 16:57:34 · answer #3 · answered by rnygelle87 2 · 0⤊ 1⤋
2x^2+8x+6
=2(x^2+4x+3)
=2(x+3)(x+1)
3x^2-12x+9
=3(x^2-4x+3)
=3(x-3)(x-1)
4x^2-x-14
=(4x+7)(x-2)
2007-10-15 16:57:11 · answer #4 · answered by Frst Grade Rocks! Ω 7 · 0⤊ 0⤋
(x+3)(2x+2)
or2(x+1)(x+3)
(3x-3)(x-3)
3(x-1)(x-3)
(4x+7)(x-2)
2007-10-15 16:56:36 · answer #5 · answered by foofy 4 · 1⤊ 0⤋