2007-10-15 16:42:51 · 9 answers · asked by Oscar 1 in Science & Mathematics ➔ Mathematics
x^2 - 13x = -12
x^2 - 13x +12= 0
(x-12)(x-1)=0
2007-10-15 16:47:09 · answer #1 · answered by Frst Grade Rocks! Ω 7 · 1⤊ 0⤋
Whenever you are trying to factor a quadratic equation, it must be equal to zero. So, first you must change the equation so that it is equal to zero.
x^2 - 13x = -12
x^2 - 13x + 12 = 0
The next step is to find out what 2 numbers can multiply to get 12, but also can be added to get -13.
The two numbers that seem to work are -12 and -1
(x - 12)(x - 1) = 0
2007-10-15 16:50:01 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^2 -13x = -12
x^2 - 13x +12 = 0
(x - 1) (x - 12) = 0
factors or roots:
x - 1 = 0 x - 12 = 0
x = 1 x = 12
factors are 1 and 12
2007-10-15 16:48:41 · answer #3 · answered by rnygelle87 2 · 0⤊ 0⤋
equate to zero by adding 12 to both sides:
x^2 - 13x +12 = 0
(x-12) (x-1) = factors
2007-10-15 19:19:03 · answer #4 · answered by criselda 3 · 0⤊ 0⤋
x^2-13x=-12
(x-13) (x+1)=12
2007-10-15 16:50:58 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x^2 - 13x = -12
x^2-13x+12=0
(x-12)(x-1)=0
x=12
x=1
2007-10-15 16:55:00 · answer #6 · answered by ptolemy862000 4 · 0⤊ 0⤋
x^2 - 13x = -12
add 12
x^2 - 13x + 12 = 0
x^2 - 12x - x + 12 = 0
x(x-12) - 1(x-12) = 0
(x-12)(x-1) = 0
x = 12 or 1
2007-10-15 16:50:14 · answer #7 · answered by mohanrao d 7 · 0⤊ 0⤋
x ² - 13 x + 12 = 0
( x - 12 ) ( x - 1 ) = 0
x = 12 , x = 1
2007-10-15 23:00:16 · answer #8 · answered by Como 7 · 0⤊ 0⤋
6x^2+13x+6=[6*6=36 factor of 36=9*4 and the sum of 4+9=13]= =6x^2+4x+9x+6= =2x(3x+2)+3(3x+2)= =(3x+2)(2x+3)
2016-04-09 01:46:04 · answer #9 · answered by Anonymous · 0⤊ 0⤋