a superball question for physics.?

Question

A superball of mass m is dropped vertically from a height, h. If the impact time with the floor is {delta}t, what is the average force on the ball? (Assume that the superball bounces back to the same height.)

I think the answer is :

(m*(gh)^0.5)/(2*{delta}t)

is this right? if not, what part is wrong?

Answer 1

Not right, but only wrong by a scale factor. Expressed most simply, acceleration = ΔV/Δt = 2V/Δt, so F = 2mV/Δt.
In terms of g and h, V = (2gh)^0.5, so
F = 2m*(2gh)^0.5/Δt
= (m*(gh)^0.5)/(2Δt) * 2*2*2^0.5
= your equation * 2^2.5