2007-10-15 14:06:35 · 7 answers · asked by Onika D 1 in Science & Mathematics ➔ Mathematics
This quadratic has no recognizeable factors. If you have been taught how to use the quadratic formula, this does have two irrational roots.
{-6 ±(√36 - 4)} / 2
(-6 ± √32) / 2
(-6 ± 4√2) / 2
-3 ± 2√2
2007-10-15 14:23:27 · answer #1 · answered by Don E Knows 6 · 0⤊ 0⤋
x^2 + 6x + 1 = 0
(x + 3) (x + 2) = 0
x = -3 or x = -2
2007-10-15 21:14:55 · answer #2 · answered by ♪£yricảl♪ 4 · 0⤊ 1⤋
x^2 + 6x + 1 = 0
use quadratic equation
x= -6 + or - sqroot of 6^2 - 4(1)(1) whole thing divided by 2(1)
you should get x= -6 +or- sqroot of 32 whole thing divided by 2
2007-10-15 21:22:23 · answer #3 · answered by Essential 3 · 0⤊ 0⤋
X^2 + 6x + 1 = 0
-1 -1
X^2+6x=-1
/6 /6
2X^2=-.2
/2 /2
X^2=-.1
ANSWER=-0.32
it might not be right b/c its not the time for my brain to be functioning but thats what i got...
2007-10-15 21:21:52 · answer #4 · answered by lalala 2 · 0⤊ 1⤋
x = [- 6 ± â32 ] / 2
x = [- 6 ± 4â2 ] / 2
x = - 3 ± 2â2
2007-10-16 06:40:36 · answer #5 · answered by Como 7 · 0⤊ 0⤋
Agreed, this is already as simple as it gets... you sure you've got this entered correctly?
2007-10-15 21:16:04 · answer #6 · answered by tyghor 2 · 0⤊ 1⤋
You can't do anything with that with that information...it's already simplified.
2007-10-15 21:13:06 · answer #7 · answered by Anonymous · 0⤊ 1⤋