Two identical blocks of mass m=2.35 kg each start out at rest at height h=1.63m above ground. Block 1 will fall directly down when released. Block 2 will slide down a frictionless ramp of angle 22 degrees. Using Conservation of Energy, (a) find the final speed v of Block 1 in the moment before it hits the ground, and (b) find the final speed v of Block 2 in the moment before it touches the ground.
I've got part (a) I think but I'm not sure, and part (b) is giving me fits. Anyone know how to do something like this?
2007-10-15 14:04:24 · 1 answers · asked by Big Thinker 3 in Science & Mathematics ➔ Physics
I think I know why :-)
a) Speed is speed so it is the same regardless.
Ke=Pe so
0.5mg=mgh
However
b) Hint:Similar to a) but the sliding block will touch the ground with its vertical component.
So...
2007-10-15 14:29:50 · answer #1 · answered by Edward 7 · 0⤊ 0⤋