A physics question?

Question

A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 605 m/s. The barrel is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.045 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

Answer 1

S=Vt
t=sqrt(2 h /g)
S=V sqrt(2 h /g)
S= 605 sqrt( 2 x 0.045/9.81)=
S=58m