A man is traveling 9.8 m/s. When he reached his destination he was traveling 31.6 m/s. He knows his acceleratin was 5 m/s (2nd power). How long did it take him to get there. PLEASE SHOW WORK, it will help me do the rest of these questions. Appreciate any help I can get
2007-10-15 12:55:08 · 3 answers · asked by Lexie. 1 in Science & Mathematics ➔ Physics
Ok, you would use a kinematics equation....
Vf = Vi + at
Vf is our final velocity, which is 31. 6 m/s.
Vi is our initial velocity, which is 9.8 m/s.
a is the acceleration, which is 5 m/s/s.
...and then we are solving for t....so...
(31.6) = (9.8) + (5) (t)
21.8 = 5t
t = 4.36 seconds
2007-10-15 13:02:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Speed and acceleration are related by:
v = v0 + at where v0 is starting speed, a is acceleration, and t is time.
SOlve for time, t
t = (v-v0)/a = (31.6 - 9.8)/5 = (21.8)/5 = 4.44 s
2007-10-15 20:02:40 · answer #2 · answered by nyphdinmd 7 · 0⤊ 0⤋
In your physics text book you will find one of the three main equations in the kinematics section useful. Perhaps you can derive from first principles?
2007-10-15 20:00:20 · answer #3 · answered by Joshua 2 · 0⤊ 0⤋