algebra help!?

Question

1. 2= |1=3x|

2. solve for y in the equation C=3x(to the second power) = y

3. the ideal surface area of a balll is 51.25 square inches. The company inspector insists that the balls vary no more than 0.3 inches squared of this total. Find the minimum and maximum value for the area of the rubber balls.

Answer 1

2= |1+3x|
1+3x = 2 --> x =1/3
1+3x = -2 --> x = -1

C = 3x^2 +y
y = C-3x^2

51.25 +.3 = 51.55 max
51.25 -.3 = 50.95 min