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These need to be simplified . I keep getting the wrong answer when i do it . can you please show work ! thanks so much .

1. 3x^2-2[x-(3-2x)] = 3(x-2)^2

2. 7-[x+(3-2x)] = [-(2x-4)-18]+x

3. 4[5y-4(y-1)] = 3[4(y+1)-7y]

4. 5-3(x-3) = 3-2x

5. 4y-(5y-1) = 5

2007-10-15 12:29:01 · 3 answers · asked by thegreatescape5 2 in Science & Mathematics Mathematics

3 answers

1. 3x^2-2x+6-4x=3(x^2-4x+4)
3x^2-6x+6=3x^2-12x+12, combine all similar terms
3x^2-6x+6-3x^2+12x-12=0
6x-6=0
6(x-1)=0

2. 7-x-3-2x=-2x+4-18+x
18-2x=0

3. 20y-16y+16=12y+12-21y
13y+4=0

4. 5-3x+9=3-2x
11-x=0

5.4y-5y+1=5
-y-4=0

2007-10-15 12:43:59 · answer #1 · answered by criselda 3 · 0 0

1)

3x^2 - 2[x-(3-2x)] = 3(x-2)^2

3x^2 - 2[x - 3 +2x]=3(x-2)^2

3x^2 - 2[3x -3] = 3(x-2)^2

3x^2 -6x + 6 = 3(x-2)^2

3(x^2 - 2x + 2) = 3(x-2)^2

3[x^2 - 4x +4 + 2x - 2] = 3(x-2)^2

3[(x - 2)^2 + 2x - 2] = 3(x-2)^2

3(x-2)^2 + 3(2x - 2) = 3(x-2)^2

subtract 3(x-2)^2

3(2x-2) = 0

2x-2 = 0

2x = 2

x = 1

2)

7-[x+(3-2x)= [-(2x-4)-18]+x

7 -[x + 3 - 2x] = [-2x + 4 - 18] + x

7 -[3 -x]= [-2x-14] +x

7 - 3 + x = -2x - 14 + x

4 + x = -x - 14

2x = -18

x = -9

3)

4[5y-4(y-1)] = 3[4(y+1) - 7y]

4[5y - 4y + 4] = 3[4y + 4 - 7y]

4[y+4] = 3[4 - 3y]

4y + 16 = 12 - 9y

13y = -4

y = -4/13

4)

5- 3(x-3) = 3-2x

5- 3x + 9 = 3 - 2x

14 - 3x = 3 - 2x

11 = x

5)

4y - (5y-1) = 5

4y - 5y + 1 = 5

-y = 4

y = -4

2007-10-15 13:06:10 · answer #2 · answered by mohanrao d 7 · 0 0

1. 3x^2-2[x-(3-2x)] = 3(x-2)^2
3x^2 -2[x -3+2x] = 3(x^2-4x+4)
3x^2 -6x +6 = 3x^2 -12x +12
6x=6
x=1

2. 7-[x+(3-2x)] = [-(2x-4)-18]+x
7 -x-3+2x = -2x+4-18+x
-x +2x+2x-x = 4 -18 -7
2x = -21
x = -10.5

3. 4[5y-4(y-1)] = 3[4(y+1)-7y]
4[5y-4y+4] =3[4y+4-7y]
4y+16 =-9y +12
13y = -4
y = -4/13

4. 5-3(x-3) = 3-2x
5 -3x+9 = 3 -2x
-x = 3 -14=-11
x = 11

4y -(5y-1)=5
4y -5y+1 = 5
-y = 4
y = -4

2007-10-15 12:59:43 · answer #3 · answered by ironduke8159 7 · 0 0

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