Okay so um...I hope someone can help me in this 'cause this question is really frustrating!!! By the way this is grade 10 math.
The area of a right triangle is 6x^2+x-2. Determine the length of the base if the height is 2x-1.
2007-10-15 12:18:38 · 3 answers · asked by virtue 1 in Science & Mathematics ➔ Mathematics
Just think about it. height x width /2 = area
so (2x-1) * (w) = 6x^2+x-2. where w= width
6x^2+x-2 / 2x-1 is (3x+2)
I know this because you can first of all apply long division to polonomials (which the web should provide help in learning thsi) or if you aren't suppose to know this. Just factor 6x^2+x-2 so that one of its roots is 2x-1 and you'll get 3x+2
Hope this helps
2007-10-15 12:28:42 · answer #1 · answered by Bridgeofstraws 2 · 0⤊ 0⤋
This is very simple question
area of triangle = bh/2 , where b = base and h = height
6x^2 + x -2 = b(2x-1)/2
multiply with 2
b(2x-1) = 2(6x^2 + x - 2)
b(2x-1) = 2(6x^2 -3x + 4x - 2)
factorize RHS
b(2x-1) = 2[3x(2x-1) +2(2x-1)]
b(2x-1) = 2(2x-1)(3x+2)
divide by 2x-1
b = 2(3x+2)
b = 6x + 4
2007-10-15 19:31:55 · answer #2 · answered by mohanrao d 7 · 0⤊ 0⤋
A = bh/2 ---> b =2A/h
b= 2( 6x^2+x-2)/(2x-1)
b = (2x-1)(6x+4)/92x-1)
b= 6x+4
2007-10-15 19:33:09 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋