can someone please explain to me how I would solve this (x+4)^2=40 using the square root property?

Answer 1

Take the square root of both sides:
x + 4 = sqrt(40)

But you have to remember that there are *two* square roots (positive and negative) so:
x + 4 = ± sqrt(40)

Subtract 4 from both sides:
x = -4 ± sqrt(40)

You can simplify a little here if you like:
x = -4 ± 2 sqrt(10)

Anyway there is your answer...

Answer 2

(x+4)^2=40 (root each side to cancel the ^2)

x+4="plus or minus" "square root of 40" (Subtract 4 from each side)

Now we will have 2 equations:
1. x = -4 - "square root of 40"
2. x = -4 + "Square root of 40"

Then solve from there
1. x = -4 - ~6.3245 = -10.3245
2. x = -4 + ~6.3245 = 2.3245

Hope this helps.

Answer 3

to get rid of the ^2, you have to do the opposite, square both sides.

so the square root of x+4=square root of 40

Answer 4

(x+4)^2 = 40, take the square root of each side:

x + 4 = +/- (rt40),

x = +/- (rt40) - 4.

I`m sure you can calculate that.