x( x + 8) - (5x^2 + 3x)
thankss.
2007-10-15 10:39:15 · 7 answers · asked by ME 2 in Science & Mathematics ➔ Mathematics
First you need to multiply through the first equation by the x on the outside of the ()
x^2 + 8x - 5x^2 -3x ( the 3x turned to a negative 3x because of the - outside of the ())
Now just combine like terms
-4x^2 + 5x
Now factor out a x, because they have an x in common
x(-4x + 5)
2007-10-15 10:42:39 · answer #1 · answered by Ms. Exxclusive 5 · 0⤊ 2⤋
first you need to distribute
x(x + 8) - (5x^2 + 3x)
x^2 + 8x - 5x^2 - 3x now combine like terms
-4x^2 + 5x and you can pull an x out the say x(4x + 5) and that depends on your teacher and what they want.
2007-10-15 17:44:39 · answer #2 · answered by Richard B 3 · 0⤊ 1⤋
x^2+8x - 5x^2-3x
-4x^2+5x
2007-10-15 17:49:28 · answer #3 · answered by mikeought3 2 · 0⤊ 0⤋
x( x + 8) - (5x^2 + 3x)
x^2+8x -5x^2-3x = -4x^2 +5x =
x(5-4x)
2007-10-15 17:44:00 · answer #4 · answered by Any day 6 · 0⤊ 2⤋
x(x+8) - (5x^2 +3x)
x^2+8x-5x^2+3x
>>> 6x^2+11x <<<
2007-10-15 17:45:15 · answer #5 · answered by Mariee 4 · 0⤊ 2⤋
x² + 8x - 5x² - 3x
5x - 4x²
2007-10-16 10:43:35 · answer #6 · answered by Como 7 · 0⤊ 0⤋
x² + 8x - 5x² - 3x
-4x² + 5x
x (-4x + 5)
Hope this helps.
2007-10-15 17:43:02 · answer #7 · answered by math geek 3 · 0⤊ 2⤋