could someone please explain to me, in terms a 6 yr old could understand, how to do this titration?
what is the molarity of of an NaOH solution if 48.0 mL is needed to neutralize 35.0 mL of 0.144 M H2SO4?
2007-10-15 10:32:00 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
We write the balanced equation :
H2SO4 + 2NaOH >> Na2SO4 + H2O
Moles H2SO4 = 35.0 x 0.144 / 1000 = 0.00504
the ratio between H2SO4 and NaOH is 1 : 2
1 : 2 = 0.00504 : x
x = moles NaOH needed = 0.00504 x 2 / 1 = 0.01008
Molarity = moles / L
Volume NaOH = 48.0 mL = 0.0480 L
M = moles / L = 0.01008 / 0.0480 = 0.210
I hope this help you
2007-10-16 04:18:14 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋
1. work out moles of H2SO4 (35/1000 x 0.144)
2. double this number (mole ratio)
3. multiply by 1000/48
2007-10-15 21:05:20 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋