Factorise x2+4x-7=0??

Answer 1

I'll assume you mean x^2+4x-7=0

you can use the quadratic equation or complete the square.

Complete the square:
x^2+4x+4-11=0
(x+2)^=11
x+2=+or- √11
x=-2 +√11
x=-2 -√11

Quadratic equation:
Given: ax^2+bx+c=0 x=(-b+or-√(b^2-4ac))/2a

so x=(-4 +/- √(4^2-4*-7))/2
x=(-4 +/- √(16+28))/2
x=(-4 +/- √(44))/2
x=(-4 +/- √(4*11))/2
x=(-4 +/- 2√11)/2
x=-2 +/- √11

This gives you a solution but you said you wanted it factored. Sooo....

(x+2-√11))(x+2+√11)=0 is the factored problem.

Answer 2

X 2 4x 7

Answer 3

In order to factor x² + 4x - 7, there would have to be factors of 7 that subtract to make 4. There aren't. But you can solve the equation using "completing the square."

x² + 4x - 7 = 0
x² + 4x = 7
x² + 4x + 4 = 7 + 4
(x + 2)² = 11
x + 2 = ± √11
x = -2 ± √11

Answer 4

a million. (x + 6)(x - 4) 2. (x - 9)(x - 3) 3. (x - 5)(x - 7) 4. (x - 10)(x + 8) ____________ the main right this is to look for numbers that upload as much as the quantity interior the middle, and characteristic a made of the final quantity. as an occasion 6 + (-4) = 2, and 6(-4) = -24.

Answer 5

This equation isn't factorable. You may also say that this equation is prime. Although you cannot solve by factoring, you can solve by another method such as the quadratic formula or completing the square.

COMPLETING THE SQUARE:
(x+2)^2 = 11
x + 2 = ±√11
x = -2 ± √11

QUADRATIC FORMULA:
-4 ± √44
-------------
2

-4 ± 2√11
--------------
2

-2 ± √11

Answer 6

Think this shoulld read x^2 + 4x -7= 0

(x+4)(x)=7

(-b +/- root of B^2 -4ac) / 2a
-4

Answer 7

i dont think that can be done because there are no factors for seven that can make four, I think thats how you do these, but what do I know I only got a C2 in pass maths in the leaving cert.

Answer 8

Amazing... even in my 13 and a half year of college I still can't do that...

I think you have to add seven to both sides, then figure out what "x" is...

Answer 9

No!

Do your own homework!

Answer 10

Uhhhh.... = headache?

: )