physics help plzzzzzzz?

Question

a speeding car is traveling at 92 km/h towards a police car at rest, facing the same direction as the speeding car. If cop car begins accelerating when speeding car is 250 m behind the cop car,then what must the cop car's acceleration be in order for the cop car to reach the speeding car's velocity at the moment the speeding car catches up? Assume that the speeding car doesn't slow down.

Please show all work necessary; Use one of the five kinematics equations...thanks!!!

Answer 1

If we take the position of the speeding car as x=0 at t=0, then the police car is at x=250 at t=0

the speed of the speeding car is 92 km/ hr or
92*0.278 m/s
=25.576 m/s

so
x1(t)=25.576*t
and
x2(t)=250+.5*a*t^2

also
v2(t)=a*t
and
when the catch occurs
x1=x2
and
v2=25.576

25.576=a*t

25.576*t=250+.5*25.576*t

t=500/25.576
=19.55 s

a=25.576/19.55

a=1.31 m/s^2

j

Answer 2

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