Physics-Electron flow Problem?

Question

A current of 86mA exists in a metal wire. How many electrons flow past a given cross-section of the wire in 10.1 min?

Thanks for your help!

Answer 1

The ampere, in practice often shortened to amp, (symbol: A) is a unit of electric current, or amount of electric charge per second. The ampere is an SI base unit, and is named after André-Marie Ampère, one of the main discoverers of electromagnetism

A mA or milli-Amp is 1/1000 of an amp

The unit of charge, the coulomb, is defined, as a derived unit, to be the amount of charge displaced by a one ampere current in the time of one second.

As a result, electric current is also the time rate of change or displacement of electric charge. One ampere represents the rate of 1 coulomb of charge per second.

One mA represents 1/1000 of a coulomb of charge per second

A coulomb is equal to 6.241×10^18 elementary charges.

86/1000 of a coulomb would be (6.24100 * (10^18) * 86) / 1 000 = 5.36726 × 10^17= elementary charges.

(it doesn't matter what the cross section of the wire is)

Answer 2

time = 10.1 min * (60 s/min) = 606 s

1 mA = 0.001 Coulombs/s (or C s^-1)

Each electron carries a charge of 1.6 x 10^-19 Coulombs

86mA*(0.001 C s^-1/mA)*(1 electron/1.6 x 10^-19 C)*(606 s)

= 3.25725 x 10^20 electrons flowing past the x-section

Answer 3

present day consistently flows from the advantageous terminal to the unfavorable terminal. So on your case the present will circulate from the advantageous terminal, interior the process the circuit of the motor and end on the unfavorable terminal. yet process electron circulate is opposite to present day circulate. Electrons originate from the unfavorable terminal of the battery(unfavorable terminal is wealthy in extra electrons and subsequently is spoke of as unfavorable) circulate interior the process the circuit and terminate on the advantageous terminal(it relatively is undesirable in electrons and so attracts electrons)