Trigonometry Help Plz!?

Question

Reduce the following expression to lowest terms:

x^2 + 6x + 8 / 5x^2 - 80

Answer 1

thats not trig.

thats algebra.

either way, sorry, cant help.

Answer 2

(x^2 + 6x + 8)/(5x^2 - 80)
= (x+2)(x+4)/[5(x+4)(x-4)]
= (x+2)/[5(x-4)], x ≠ -4
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The original expression can be reduced to (x+2)/[5(x-4)] under the condition x ≠ -4. When x = -4, (x^2 + 6x + 8)/(5x^2 - 80) is undefined, while (x+2)/[5(x-4)] = .15.

Answer 3

x^2 + 6x +8 = (x+2) (x+4)
5x^2 - 80 = 5(x^2 -16) = 5((x+4) (x-4))

substituting the value:
(x+2) (x+4)/5((x+4)(x-4))

cancel x+4

(x+2)/5(x-4) = (x+2)/(5x-20) ~ final answer

Answer 4

(x^2+6x+8)/5x^2-80) factor numerator and denominator
((x+2)(x+4))/5(x+4)(x-4) cancel the (x+4)

(x+2)/5(x-4)

Answer 5

first take numerator & reduce it
x^2+6x+8=0
x^2+4x+2x+8=0
x(x+4)+2(x+4)=0
(x+4)(x+2)=0


now reduce the denominator
5(x^2-16)
5(x-4)(x+4)

now bring it together
[(x+4)(x+2)]/[5(x-4)(x+4)]

now the x+4 gets cancelled leaving us with

x+2/5(x-4)
this is the final answer

Answer 6

(x + 4)(x + 2) / 5(x² - 16)
(x + 4)(x + 2) / 5(x - 4)(x + 4)
(x + 2) / 5(x - 4)

Answer 7

(x+2)(x+4) / 5(x^2-16)

(x+2)(x+4) / 5(x-4)(x+4)

(x+2) / [5(x-4)]

Answer: (x+2) / (5x - 20)

Happy Halloween!

Answer 8

@Josephine thank you for the loose textbook! On-subject count: the toughest trigonometry questions are once you are the single that could desire to offer your self a query. working example, attempt to teach something that isn't everyday to mankind, or a minimum of no longer everyday to you.

Answer 9

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