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5 answers

the ball would NOT hit 1st b./c it also has more inertia to overcome. They balance out.

EDIT: man every time i repsond to another post they delete it. The ball and feath hit at the same time in a vacuum b/c even though the bal has more gravitational attraction to the planet, it also has more inertia to overcome.

2007-10-15 10:07:15 · answer #1 · answered by Anonymous · 0 1

The acceleration due to gravity is the same for all objects on earth. There is also an acceleration due to gravity on the moon that is equal for all objects up there as well. So on earth, if you released a feather and a steel ball from the same height, the steel ball would fall much quicker than the feather. This is because the feather encounters a great deal more air resistance and cannot fall as fast. Feathers are good at providing air resistance, that's why birds use them. On the moon however, there is virtually no atmosphere, so the effect of air resistance is negligible. If one were to drop the steel ball and feather from the same height on the moon, strangely enough they would fall at the same rate. This is because the acceleration due to gravity is the same for all objects.

2016-05-22 19:25:17 · answer #2 · answered by ? 3 · 0 0

In a simple observation, the ball on the moon would fall at the same rate as the feather because air resistance won't interfere with the feather the way it would on Earth.

However, a super-accurate observation will show the ball hit slighty before the feather, because it has more 'gravity ' of it's own. We're talking nano seconds.

2007-10-15 08:20:06 · answer #3 · answered by Anonymous · 0 1

On the moon there is no air so both will behave the same. On the earth the feather will be slowed more than the ball by air resistance.

2007-10-15 08:03:44 · answer #4 · answered by David C 5 · 1 0

if dropped from the same height, they should impact the moons surface at the same time. this would be true on earth if the feather didn't "float" on the air.

2007-10-15 08:08:51 · answer #5 · answered by Loren S 7 · 1 0

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