Math Help PLEASE!? Thanks!?

Question

How do I Solve the following equation for by using the quadratic formula:

3x^2 - 3x - 7 = 0

(If there is more than one solution, separate them with commas.)

Answer 1

3x^2 - 3x - 7 = 0
Use quadratic equation which is

ax^2 + bx + x = 0
x =[ -b±√(b^2 - 4ac)] / 2a

so a = 3
b = -3
c = -7

plug it in and you will get two answers.. one with + and whatever is inside √ and another with - √

Answer 2

Quadratic Formula

x = - b ± √b² - 4ac / 2a

3x² - 3x - 7 = 0

a = 3

b = - 3

c = - 7

x = - (- 3) ± √(- 3) - 4(3)(- 7) / 2(3)

x = 3 ± √9 - (- 84) / 6

x = 3 ± √9 + 84 / 6

x = 3 ± √93 / 6

x = 3 ± 9.643650761 / 6

- - - - - - - -

Solving for +

x = 3 + 9.643650761 / 6

x = 12.64365076 / 6

x = 2.107275127

- - - - - - -

Solving for -

x = 3 - 9.643650761 / 6

x = - 6.643650761 / 6

x = - 1.107275127

- - - - - - - s-

Answer 3

Use the quadratic formula: -b +/- (sqrt((b^2-4ac))/2a). a = 3, b = -3, c = -7, (they're the coefficients of the x^2, x, and the constant, respectively.

So x = (3 +/- sqrt(9-4(-7)(3)))/6 = (3 +/- sqrt(93)) /6. So your two answers are [3 + sqrt(93)]/6 and [3 - sqrt(93)]/6.

Answer 4

3x^2 - 3x - 7 = 0

For the general quadratic

ax^2 + bx + c = 0

the formula is

x = [- b +- sqrt(b^2 - 4ac)]/2a

Answer 5

it's
D=3^2-4*(-7)*3
=9+84
=93
X1=(-3+[square root of D])/2*3)
and X2=(-3-[square root of D)/2*3
and you got x=to something and x= to something else!!!
if this is what you want

Answer 6

3x^2 - 3x - 7 = 0
or 3x^2 -7x + 3x - 7 = 0
or x(3x -7) + (3x -7) = 0
or (x + 1)(3x - 7) = 0
either x = -1
or x = 7/3

Answer 7

use quadratic formula

......-b ± √ b^2 - 4 (a)(c)
x = ----------------------------
.................2(a)
where, a = 3
...........b = -3
...........c = -7