Block of lead?

Question

A block has a mass of 5.87 kg and density of 496 kg/m^3. A piece of lead is placed on top of the block, adn the sytem floats in water. It is observed that 0.736 of the block's volume is submerged. The density o f lead is 11.3x10^3 kg/m3.

1. What is the mass of the lead?

2. The lead is removed from the top, and a different piece of lead is attached to the bottom of the block. Its mass is such that the same 0.736 of the block's volume is subermged. It shi mass greater than, less than or equal to the mass found in Question 1? Explain

Please help...I'm so lost.

Answer 1

Given
For block
p1=496 kg/m^3
m1=5.87 kg
V(water displaced)=V'=0.736 V1
p' - density of water=1.0 E+3kg/m^3

for lead
p2= 11.3 E+3 kg/m^3
m2=?

p' 0.736 V1=m1+m2
p' 0.736 V1=m1+m2

m2= p' 0.736 V1-m1
m2=p' 0.736 m1/p1-m1
m2=m1(0.736 p'/p1 -1)
m2=5.87 (0.736 x ( 1.0 E+3)/(496) -1)
m2= 2.84kg

2. Do you think water will try do displace that volume of submerged lead?