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2,2-Dimethyl-1- bromopropane and bromoethane, both primary alkyl halides undergo SN2. Which one of them would react slower in the reaction and why?

I know that the stronger the nucleophile, the faster the rate of the SN2 reaction, but could someone please explain how to find if one is stronger than another? I know that bromoethane has a simpler structure, but that have anything to do with this question?

Thanks for any help. :-)

2007-10-15 05:32:24 · 2 answers · asked by John D 3 in Science & Mathematics Chemistry

2 answers

The bromopropane will react slower due to steric hinderence. Since the propane group is larger/bulkier than the ethane group, the nucleophile will have a harder time attacking the bromopropane only because there is more "stuff" in the way.

2007-10-15 06:50:13 · answer #1 · answered by naps in the sun 3 · 1 0

2,2-Dimethyl-1- bromopropane

The side group is very bulky and will not have a planar config although the C from which Br leaves will. This bulk will then hinder the approach of any nucleophile.

2007-10-15 05:49:19 · answer #2 · answered by ag_iitkgp 7 · 0 0

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