An isosceles right triangle has an area 200cm^2.What is the length of its hypotenuse?

Question

An isosceles right triangle has an area 200cm^2.What is the length of its hypotenuse?

Answer 1

Let each equal side of the isosceles right angled triangle be x cm
Area of the triangle
=1/2*x^2
Therefore,
1/2*x^2=200 cm^2
x^2=400
x=20 cm
The hypotenuse of the triangle is terefore,
sqrt(20^2*2)
=20 sqrt2 cm

Answer 2

If a is the size of the two legs (equivalent given which you stated it relatively is an isosceles triangle), then via the pythagorean theorem: a² + a² = 24² or 2a² = 24² a² = 24²/2 the portion of the triangle is a×a/2 = a²/2 = 24²/4 = 576/4 = a hundred and forty four the section is a hundred and forty four feet² ProfRay

Answer 3

An isosceles triangle is one that is a 45-45-90 triangle. This is essentially a half square.

If the half square has an area of 200 cm², then the full square would have an area of 400 cm².

Taking the square root, you can see that you have sides of 20 cm.

Now using the pythagorean theorem:
a² + b² = c²

20² + 20² = c²
c² = 400 + 400
c = sqrt(800)
c = sqrt(400) * sqrt(2)
c = 20√2

c ≈ 28.29 cm

Answer 4

A=200cm^2
=> c1*c2=200 and c1=c2 because is a triangle isosceles
=> c1=10*sqrt2
=> ip^2=c1^2*c2^2
ip^2=100*2+100*2=400
=> ip=20 cm

Answer 5

(1/2)a² = 200cm²
a² = 400cm²
a = 20cm
Length of hypotenuse = sqrt(2)a = 20sqrt(2) cm