2007-10-15 03:50:30 · 5 answers · asked by Onika D 1 in Science & Mathematics ➔ Mathematics
x^2 -13x +12 =0
(x - 1) * (x - 12) = 0
x = 1
x = 12
2007-10-15 03:54:33 · answer #1 · answered by tfloto 6 · 0⤊ 0⤋
x^2-13x+12=0
(x-12)(x-1)=0
x=12 and 1
prove.
x times x = x^2 than x times -1 = -x than -12 times x = -12x and -12 times -1 = 12 so. x^2-x-12x+12=0
=x^2-13x+12=0
=x^2-13x-12
o heres the quad....
[13+and- square Root(13^2-(4*1*12))]/2
=[13+and- square Root(121)]/2
=(13+11)/2 and =(13-11)/2
=24/2 and 2/2
so the answers are 12 and 1
2007-10-15 10:56:30 · answer #2 · answered by Mike 1 · 0⤊ 0⤋
x^2 - 13x = -12
x^2 - 13x + 12 = 0
(x - 12)(x - 1) = 0
x = 12 or 1
2007-10-15 12:01:27 · answer #3 · answered by Kemmy 6 · 0⤊ 0⤋
x ² - 13 x + 12 = 0
(x - 12) (x - 1) = 0
x = 12 , x = 1
2007-10-15 14:37:38 · answer #4 · answered by Como 7 · 0⤊ 0⤋
x^2 - 13x + 12 = 0
Use the quadratic equation
2007-10-15 10:53:20 · answer #5 · answered by Anonymous · 0⤊ 0⤋