Who is your pick to win the worl series and who will they play and by how many games
2007-10-15 03:27:42 · 21 answers · asked by bravesmanic 2 in Sports ➔ Baseball
The Rockies in 5 games over Cleveland with one game going into extra innings.
2007-10-19 03:24:41 · answer #1 · answered by Anonymous · 0⤊ 1⤋
I'm guessing that it will be Colorado & Boston in the WS. Boston gets the home-field advantage (thanks to Bud Selig's idiotic rule concerning the All-Star Game), which helps take away a little of Colorado's offensive firepower. In the end, I'd favor Boston to win it in six games. Colorado has been playing some great ball, but it will be their first WS, and I just don't know about that pitching staff of theirs.
As an Atlanta fan, my real answer, though, is "unfortunately, it won't be the Braves." I guess there's always next year.
:)
2007-10-15 13:36:28 · answer #2 · answered by Dan S 2 · 0⤊ 1⤋
Rockies over Sox in 6
2007-10-15 10:30:15 · answer #3 · answered by rikirailrd 4 · 2⤊ 3⤋
Red Sox in 7. I am a Rockies fan and hope they win but Colorado just doesn't have the depth to completely shut down the Boston offense, especially with four games at Fenway.
2007-10-15 11:07:48 · answer #4 · answered by mrj171 2 · 0⤊ 4⤋
Rockies over Indian in 5
2007-10-15 11:26:08 · answer #5 · answered by kevin s 2 · 1⤊ 3⤋
Cleveland vs Colorado.
Rockies in 5 games.
2007-10-15 10:30:18 · answer #6 · answered by Greddy 2 · 2⤊ 3⤋
Colorado over Red Sox- 4 wins, 1 loss.
I'm a Tiger's & D-Backs fan-maybe next year.
2007-10-15 10:30:22 · answer #7 · answered by WooleyBooley again 7 · 2⤊ 3⤋
this is what I hope it will be Indians & Rockies
Indians will win in 5 or 6, but there is still a long long road ahead to try and get past the Red Sox.
2007-10-15 11:35:15 · answer #8 · answered by Anonymous · 3⤊ 2⤋
Rockies in 5 games.
I'd love to see them kick the red sox's asses all over the field.
2007-10-15 10:29:57 · answer #9 · answered by tiny Valkyrie 7 · 4⤊ 2⤋
rockies and red sox
rockies sweep the sox
2007-10-15 17:36:33 · answer #10 · answered by Anonymous · 0⤊ 1⤋