Factor completely?

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6x^2y-2xy-60y this one has bugging me for two days, help!

2007-10-15 03:22:51 · 6 answers · asked by Cat C 1 in Science & Mathematics ➔ Mathematics

take out a factor of 2y first

2y(3x^2-x-30)

then factor bracket

2y(3x-10)(x+3)

2007-10-15 03:31:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋

6x^2y -2xy - 60y
= 2y(3x^2 - x - 30)
= 2y(3x - 10)(x + 3)

2007-10-15 10:38:50 · answer #2 · answered by Don E Knows 6 · 0⤊ 0⤋

2y ( 3 x Â² - x - 30 )
2y ( 3 x - 10 )( x + 3 )

2007-10-15 14:33:38 · answer #3 · answered by Como 7 · 0⤊ 0⤋

= 2y(3x-10)(x+3)

2007-10-16 10:06:41 · answer #4 · answered by Chris 3 · 0⤊ 0⤋

2y(3x^2-x-30)
2y((3x-10)(x+3))

2007-10-15 10:32:44 · answer #5 · answered by les 4 · 0⤊ 0⤋

2y(3xÂ²-x-30)

2007-10-15 10:32:10 · answer #6 · answered by Anonymous · 0⤊ 0⤋