How many joules?

0 ⤊

Calculate q when 0.10 g ice is cooled from -23°C to -75°C (cice = 2.087 J/g·K).

2007-10-15 01:55:37 · 3 answers · asked by jnester0289 1 in Science & Mathematics ➔ Chemistry

3 answers

specific heat * change in temperature * mass

2.087 J/g·K * 52 degrees * .1 g
2.087 * 52 * .1 = 10.85 joules

2007-10-15 02:00:43 · answer #1 · answered by DanE 7 · 0⤊ 0⤋

easy... just look at ur units. You want to get Joule so...

q = 2.087 · 0.10 · (75-23) = 10.85 J

So you will need 10.85 Joule in order to cool down the ice from -23°C to -75°C.

2007-10-15 02:01:25 · answer #2 · answered by Marcus Paul 3 · 0⤊ 0⤋

2.5

2007-10-15 01:58:19 · answer #3 · answered by Fuzzybutt 7 · 0⤊ 0⤋