(cos(^2)x)cosecx = cosecx - sinx
Note: the (cos(^2)x) is cos squared times x not cos to the power 2x.
any help would be appreciated.
:)
2007-10-15 01:17:22 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(cosX)^2 cscx
[1 - (sinX)^2] cscX
[1 - (sinX)^2] (1/sinX)
1/sinX - sinX
cscX - sinX
2007-10-15 01:27:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Substitute 1/sinx for cosecx into your equation. Then multiply both sides by sinx. This gives
cos^2x=1-sin^2x
rearranged cos^2x+sin^2x=1 hence identity is proven.
2007-10-15 12:20:30 · answer #2 · answered by betty 1 · 0⤊ 0⤋
Remember that csc x is the reciprocal of sin x, thus it can be expressed as 1/sin x
cos^2x( 1/sin x) = 1/ sin x - sin x, simplify:
cos^2 x/sin x = 1 - sin^2 x/ sin x, now multiply both sides by sin x to cancel out the denominator
cos^2 x = 1 - sin^2 x, The Pythagorean Identities states that sin^2 x + cos^2 x = 1... therefore:
cos^2 x = 1 - sin^2 x
Hope this helps...
2007-10-15 08:37:26 · answer #3 · answered by criselda 3 · 0⤊ 0⤋
cos^2 x cosecx = cos^2 x / sinx
= (1 - sin^2 x) / sinx
= cosecx - sinx
2007-10-15 08:29:08 · answer #4 · answered by Dr D 7 · 0⤊ 0⤋
(1-sin^2x)cosecx = cosecx -sinx
cosecx - sin^2xcosecx
cosecx - sin^2x(1/sinx)
cosecx -sinx ****proven
2007-10-15 08:41:34 · answer #5 · answered by Synchronizers 3 · 0⤊ 0⤋
Ask the police for their book of mug-shots, this will help you get this identity(if he is in their records)
2007-10-15 09:16:28 · answer #6 · answered by BAZEBO 2 · 0⤊ 0⤋
LHS
cos ² x / sin x
(1 - sin ² x) / sin x
1/sin x - sin x
cosec x - sin x
RHS
cosec x - sin x
LHS = RHS
2007-10-16 04:32:49 · answer #7 · answered by Como 7 · 0⤊ 0⤋
identity fraud is a growing problem
2007-10-15 08:22:48 · answer #8 · answered by Anonymous · 0⤊ 0⤋