Evaluate 4x^3 + 2x^2 – 1 for x = 1
Thanks for the help!
2007-10-15 00:59:24 · 9 answers · asked by Pete 1 in Science & Mathematics ➔ Mathematics
4(1) + 2(1) -1
= 5
2007-10-15 01:03:00 · answer #1 · answered by mrr86 5 · 1⤊ 0⤋
4 + 2 - 1 = 5
2007-10-16 00:55:24 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Its 5
2007-10-15 01:25:11 · answer #3 · answered by amol.bhushan 2 · 0⤊ 0⤋
evaluate 4x^3+2x^2 -1 for x=1
ans: substitute 1 in the place of X
4*1^3+2*1^2-1
4+2-1
6-1
5
so the answer is 5
2007-10-15 01:13:34 · answer #4 · answered by suman 1 · 0⤊ 0⤋
4x^3 + 2x^2 – 1
= 4(1)^3 + 2(1)^2-1
= 4(1) + 2(1)-1
= 4+2-1
= 6-1
= 5
2007-10-15 01:18:12 · answer #5 · answered by Anonymous · 0⤊ 0⤋
This is really easy... just substitute 1 in all x. Remember that 1 raised to zero and all positive integer is equal to 1 so...
4(1) + 2(1) - 1 = ?
4 + 2 - 1 = 5
2007-10-15 01:12:20 · answer #6 · answered by criselda 3 · 0⤊ 0⤋
one million. The assertion is ambigous. Do you mean 4x^3+...... and so on. if so that's going to be 5. 2. only open the parentheses and then assemble a similar 'x' words. you're able to desire to arise with x^2+2x-15.
2016-12-14 18:18:55 · answer #7 · answered by behl 4 · 0⤊ 0⤋
since x=1, then we have:
4(1)^3+2(1)^2-1
=4+2-1
=5
Hope it helps!
2007-10-15 01:13:53 · answer #8 · answered by greenheaven 1 · 0⤊ 0⤋
substitute x with 1 and then try solving the problem.
2007-10-15 01:04:54 · answer #9 · answered by Anonymous · 2⤊ 0⤋