Please help me. I don't know how to work it out
2007-10-14 22:07:28 · 6 answers · asked by Maximus 5 in Science & Mathematics ➔ Mathematics
If r is the common ratio,
10 = 5 /(1 - r)
=> r = 0.5
10th term
= 5r^9
= 5(0.5)^9
= 5/512
2007-10-14 22:14:32 · answer #1 · answered by Madhukar 7 · 1⤊ 1⤋
S ∞ = a / (1 - r) = 10
5 / (1 - r) = 10
5 = 10 - 10r
r = 1/2
u 10 = a r^9
u 10 = 5 (1/2)^9
u 10 = 5 / 512
2007-10-14 23:21:55 · answer #2 · answered by Como 7 · 0⤊ 0⤋
a/(1-r)=10
a=5
hence 1-r = 0.5
thus 10 term = 5x(0.50)^9
therefore 10 term = 5/512
2007-10-14 22:32:24 · answer #3 · answered by genius 2 · 0⤊ 0⤋
5/512
2007-10-14 22:27:15 · answer #4 · answered by sachinone1 1 · 0⤊ 0⤋
r =1/2
a(10) = a(1) * r^9
a(10) = 5 * (1/2)^9
a(10) = 5/512
2007-10-14 22:15:46 · answer #5 · answered by Anonymous · 0⤊ 0⤋
enable S = sum of sequence T = sum of wierd numbered words S = a + ar + ar^2 + ar^3 + ... S(one million - r) = a S = a/(one million - r) = 8 a = 8(one million - r) T = a + ar^2 + ar^4 + ... T(one million - r^2) = a T = a/(one million - r^2) = 6 a = 6(one million - r^2) placing the two equations for a equivalent. 8(one million - r) = 6(one million - r^2) = 6(one million - r)(one million + r) 8 = 6(one million + r) 8/6 = one million + r 4/3 - one million = r one million/3 = r r = one million/3
2016-12-14 18:12:53 · answer #6 · answered by ciprian 4 · 0⤊ 0⤋