find the equation of the line that passes through th points (-2,-4) and (2,-1)?

Question

find the equation of the line that passes through th points (-2,-4) and (2,-1)

Answer 1

eqn of a line:y=mx+c,thus first find the grad...m = [-4-[-1]]/-2-2=3/4 so your y=3/4x+c now sub in one of your coord in the eqn to find c....thenpresent it in the form y=mx+c

Answer 2

First find the slope:

M = slope = (y2-y1) / (x2 - x1)
M = (-1 - (-4)) / (2 - (-2))
M = 3 / 4

Slope = 3/4


The equation of a line is:

y-y1 = M (x - x1)

Where y1 is a y of a given point on the line, x1 is the x point of a given line on the point and M is the slope. We have two point on the line but we will select the second point for example:

x1 = 2
y1 = -1
m = 3/4

y-y1 = m (x-x1)
y - (-1) = 3/4 (x - 2)
y + 1 = 3/4x - 3/2
y = 3/4x - 3/2 - 1

3/2 - 1 = 3/2 - 2/2 = 1/2 = 0.5

y = 3/4x - 0.5

That's the formula of the line.

Answer 3

Slope of the line is (-1 + 4) / (2 + 2) = 3/4
Eqn. of line through (2, -1) having slope 3/4 is
y + 1 = (3/4) ( x - 2)
3x - 4y = 10

Answer 4

the generic equation for a linear graph is y=mx+c
where m is the gradient and c is the y intercept

To find the gradient, you find the difference in y over the difference in x = (-4-(-1)) / (-2-2)
= -3/4

y= -3/4x + c

when x=2, y=-1
-1= (-3/4 x 2) +c
c= 1/2

ANS: y= -3/4x + 1/2

Answer 5

slope = (-1+4)/(2+2) = 3/4
3/4 = (y +1) /(x-2)
3(x-2) = 4(y +1)
3x - 6 = 4y + 4
3x - 4y -10 = 0

Answer 6

m = (- 1 + 4) / (2 + 2)
m = 3 / 4
y + 1 = (3/4) (x - 2)
y = (3/4) x - 3/2 - 1
y = (3/4)x - 5/2

Answer 7

use the formula, m(x-x1) = y-y1
slope: 3/4
(-2,-4) x1 and y1
3/4(x+2) = y+4
4x+6 = 4y+16
4x-4y = 10

Answer 8

well we have: (y-y1)/(x-x1)=(y2-y1)/(x2-x1) so
(y+1)/(x-2)=(-4+1)/(-2-2)
(y+1)/(x-2)=-3/-4 =3/4
4y+4=3x-6
4y-3x+10=0