You could assume that cosine was a polynomial of degree n where n is a positive integer. The Fundamental Thm of Algebra tells us that it would have at most n roots (zeroes). However, the cosine function has an infinite number of roots so it cannot be a polynomial (this is a very informal proof by contradiction).
2007-10-14 19:18:52
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answer #1
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answered by absird 5
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The reason that the cosine function is not a polynomial because there is no highest finite degree of the polynomial if you write cosine as a polynomial. The degree is infinite so it is not a polynomial. If the degree would be finite like f(x)=x^1000000 then f(x) is a polynomial.
2007-10-14 19:26:42
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answer #2
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answered by The Prince 6
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The harmonic oscillator Schroedinger equation is complicated to sparkling up. What people do is anticipate the answer has the form of a polynomial situations an errors function. while that's finished the polynomials become Hermite polynomials.
2016-12-29 10:45:22
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answer #3
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answered by ? 3
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Polynomial, by definition, is an algebraic expression with non-negative integral powers of all the variables involved and clearly cosine(x) cannot be expressed in terms of x with integral power.
2007-10-14 19:22:31
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answer #4
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answered by sulinderkumarsharma 2
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because it is a function that needs something inside of it..ie; you can't write cos by itself it needs something inside like cosx. Other functions that are not polynomials are abs value, tan, ln, etc. A polynomial is usually a variable raised to a power.
2007-10-14 19:09:46
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answer #5
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answered by shadoyaj 4
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For starters, it's periodic and bounded. Any non-constant polynomial will eventually go to +∞ or -∞ as x -> ∞, and is therefore neither periodic nor bounded.
2007-10-14 19:10:01
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answer #6
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answered by Scarlet Manuka 7
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