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I know that a cosine function isn't a polynomial, but I can't seem to name any specific reasons why. Please help!

2007-10-14 18:58:31 · 6 answers · asked by Jess 2 in Science & Mathematics Mathematics

6 answers

You could assume that cosine was a polynomial of degree n where n is a positive integer. The Fundamental Thm of Algebra tells us that it would have at most n roots (zeroes). However, the cosine function has an infinite number of roots so it cannot be a polynomial (this is a very informal proof by contradiction).

2007-10-14 19:18:52 · answer #1 · answered by absird 5 · 1 0

The reason that the cosine function is not a polynomial because there is no highest finite degree of the polynomial if you write cosine as a polynomial. The degree is infinite so it is not a polynomial. If the degree would be finite like f(x)=x^1000000 then f(x) is a polynomial.

2007-10-14 19:26:42 · answer #2 · answered by The Prince 6 · 1 0

The harmonic oscillator Schroedinger equation is complicated to sparkling up. What people do is anticipate the answer has the form of a polynomial situations an errors function. while that's finished the polynomials become Hermite polynomials.

2016-12-29 10:45:22 · answer #3 · answered by ? 3 · 0 0

Polynomial, by definition, is an algebraic expression with non-negative integral powers of all the variables involved and clearly cosine(x) cannot be expressed in terms of x with integral power.

2007-10-14 19:22:31 · answer #4 · answered by sulinderkumarsharma 2 · 0 0

because it is a function that needs something inside of it..ie; you can't write cos by itself it needs something inside like cosx. Other functions that are not polynomials are abs value, tan, ln, etc. A polynomial is usually a variable raised to a power.

2007-10-14 19:09:46 · answer #5 · answered by shadoyaj 4 · 0 2

For starters, it's periodic and bounded. Any non-constant polynomial will eventually go to +∞ or -∞ as x -> ∞, and is therefore neither periodic nor bounded.

2007-10-14 19:10:01 · answer #6 · answered by Scarlet Manuka 7 · 0 0

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