A particle is traveling along the x-axis. Its initial position is 20 meters to the right of the orgin and its final position is 125 meters to the right of the orgin. The particle travels from 20 meters to 65 meters at a velocity of 15 meters/second and from 65 meters to 125 meters to the right of the orgin at a rate of 60 meters/second. Find the average velocity of the particle as it travesl from its initial position to its final postion.
2007-10-14 18:43:22 · 4 answers · asked by lance3223 1 in Science & Mathematics ➔ Mathematics
Ave velocity = sum(v*t)/tt, tt=total time. To find tt, we look at each section of the problem. In part 1, the particle moves 15 m/sec for 3 sec [65-20 / 15]; part 2, 1 sec. So the total is 4 seconds, and the calculation is 15*3+60*1 / 4 = 105/4= 26.25 mps.
2007-10-14 18:57:50 · answer #1 · answered by cattbarf 7 · 0⤊ 0⤋
Okay well remember those nice velocity, time, distance relationships. v = d/t, t = d/v
The particle goes 45 meters at a velocity of 15 m/s
t = 45/15 = 3 seconds
It then goes 60 meters at 60 m/s
t = 60/60 = 1 second
The average velocity is then just the total distance divided by the total time.
2007-10-14 18:58:24 · answer #2 · answered by filmmakr 2 · 0⤊ 0⤋
Time from 20m to 65m = 45 / 15 = 3 sec
Time from 65m to 125m = 60 / 60 = 1 sec
Total time = 4 sec
Average velocity = 105 / 4 m/s = 26¼ m/s
2007-10-15 01:38:04 · answer #3 · answered by Como 7 · 0⤊ 0⤋
LMAO purely 8 aspects eh? communicate approximately one being below favorite! Ya basically in basic terms isn't waiting to get any comprehend in any comprehend, no longer inspite of a suited answer. LOL Brightest reward, Raji the golf green Witch
2016-12-29 10:41:47 · answer #4 · answered by guisinger 3 · 0⤊ 0⤋