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A movie ticket for an adult cost $8, and a child's ticket cost $5.50. One adult is taking a group of children to the movies. she has $35.00. How many children can she take with her to the movies?

2007-10-14 18:35:07 · 11 answers · asked by tonee12004 1 in Science & Mathematics Mathematics

11 answers

35.00 = 8 + 5.50c

c is the number of children. When you solve for c, round down to a whole number

2007-10-14 18:38:02 · answer #1 · answered by SoulDawg 4 UGA 6 · 0 0

adult cost is constant = 8.0 $
Children cost = 5.50$
so, 35-8= 27 $ divided by 5.5 will be equal to 4 children and 5 $ left for Car parking and Some small refreshment.

He and 4 children can be taken accept that he can have 5 $ for refreshment and car parking or hiring taxi.

2007-10-14 18:45:06 · answer #2 · answered by Anonymous · 0 0

35-8=n

where n is the price of the tickets of all the children.

5.50/n = c

where c is the number of children.

(What he said is really AN equation, but I like these two anyway.)

2007-10-14 18:38:20 · answer #3 · answered by Palestini Detective 4 · 0 0

let:

x- the number of children can be taken

a- adult ticket @$8
b- child ticket @$5.5
c- total cash available $35
equation:
c=a+x(b)
substitute values
$35=$8+x($5.5)
$35-$8=x($5.5)
$27 =x($5.5)
x =$27/($5.5)
x = 4.9
since no children of .9
4 children she can take

2007-10-14 18:53:41 · answer #4 · answered by bongards 2 · 0 0

W= cost of childs ticket
X=cost of adult ticket
Y=total amount of money
Z=number of children that can go

Z=(Y-X)/ W
Z= (35-8)/5.5=4.9090'
so Z= 4
4 children can go with out spending any extra money

2007-10-14 18:45:40 · answer #5 · answered by Anonymous · 0 0

35>= 8+ 5.50x
27>= 5.50x
27/5.5>=x
you will get some number between 4 and 5, so she can only take 4 children.

2007-10-14 18:39:58 · answer #6 · answered by moonman 6 · 0 0

Mary's value ticket quantity = "M" Jim's value ticket quantity = "J" M = J - a million M * J = 812 replace in (J - a million) for M (J - a million) * J = 812 J^2 - J - 812 = 0 (J - 29) (J + 28) J is in simple terms beneficial at 29 so because it is Jim's value ticket quantity, and Mary's is J - a million it is 28. J=29, M=28.

2016-10-22 11:22:07 · answer #7 · answered by finnigan 4 · 0 0

Let x be the number of children:
8 + 5.5x = 35
5.5x = 27
x = 4.90909090.....

But since she cannot take 4.909090... and cannot afford to take more than that she can take up to 4 children with her.

2007-10-14 18:39:02 · answer #8 · answered by JY 2 · 0 0

Equation

35= 8A+5.5C

We know one adult is coming

35=8+5.5c

Solve for c, we get C= 4.9

since you can't split tickets, round down.

This is really simple math. If you have to ask for something like this, I feel very sorry for your future. This obviously tells me that you don't even want to try this problem.

2007-10-14 18:41:32 · answer #9 · answered by sintosol2 2 · 0 0

8+5.5x=35

where x is the number of children

x=27/5.5

2007-10-14 18:39:42 · answer #10 · answered by Cris Y 2 · 0 0

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